Linear displacement is angular displacement cross radius

Assuming a body rotating around a fixed axis, the vector of its linear displacement can be expressed as the cross product of the pseudovector of angular displacement and the radius vector of rotation.

Conditions:

  1. The axis is fixed.

  2. Angular displacement pseudovector and radius vector must be orthogonal to one another.

Links:

  1. Physics LibreTexts, formula 11.1.4.

linear_displacement

Vector of the body’s linear displacement. See distance.

Symbol:

s

Latex:

\({\vec s}\)

Dimension:

length

angular_displacement

Pseudovector of the body’s angular displacement. See angular_distance. It is parallel to the rotation axis.

Symbol:

theta

Latex:

\({\vec \theta}\)

Dimension:

angle

rotation_radius_vector

Radius vector pointing away from the rotation axis perpendicular to it. See distance_to_axis.

Symbol:

r

Latex:

\({\vec r}\)

Dimension:

length

law

s = cross(theta, r)

Latex:
\[{\vec s} = \left[ {\vec \theta}, {\vec r} \right]\]