Time of flight of a projectile via maximum height¶

Let the body be thrown horizontally with some initial velocity. Then the time of the motion of this body until it reaches the initial elevation depends only on the height and acceleration of free fall.

Conditions:

The acceleration of gravity stays constant throughout the movement of the body.
The initial and final height of the body with respect to the “ground” are the same, i.e. the body lands on a point with the same vertical coordinate as at the start of the flight.

Links:

Physics LibreTexts. Zero Launch Angle, Duration of Flight (3.3.22).

time¶

time of flight of the projectile.

Symbol:: t
Latex:: \(t\)
Dimension:: time

height¶

Maximum height which the projectile reaches during its motion.

Symbol:: h
Latex:: \(h\)
Dimension:: length

law¶

t = sqrt(2 * h / g)

Latex:: \[t = \sqrt{\frac{2 h}{g}}\]