Time of flight of a projectile via initial velocity

Let the body be thrown at an angle to the horizon with some initial velocity. Then the time of the motion of this body until it reaches the initial elevation depends only on initial velocity and acceleration of free fall.

Conditions:

1. The acceleration of gravity stays constant throughout the movement of the body.

2. The initial and final height of the body with respect to the “ground” are the same, i.e. the body lands on a point with the same vertical coordinate as at the start of the flight.

Links:

1. Physics LibreTexts. Projectile Motion, Maximum Height (3.3.13).

time

time of flight of the projectile.

Symbol:

t

Latex:

\(t\)

Dimension:

time

initial_speed

Initial speed of the projectile.

Symbol:

v_0

Latex:

\(v_{0}\)

Dimension:

velocity

angle

angle

Symbol:

phi

Latex:

\(\varphi\)

Dimension:

angle

law

t = 2 * v_0 * sin(phi) / g

Latex:

\[t = \frac{2 v_{0} \sin{\left(\varphi \right)}}{g}\]