Neutron flux for uniform slab
=============================
Neutron flux for a reactor in the shape of an infinite slab of finite thickness depends
on the orthogonal distance to the plane of symmetry inside the slab.
**Links:**
#. `NuclearPower, see end of page `__.
.. py:currentmodule:: symplyphysics.laws.nuclear.buckling.neutron_flux_for_uniform_slab
.. py:data:: dimension_factor
Dimension factor that appears as a coefficient in the solution to the :ref:`differential
equation `. See :attr:`~symplyphysics.symbols.nuclear.neutron_flux`.
Symbol:
:code:`Phi_0`
Latex:
:math:`\Phi_{0}`
Dimension:
:code:`1/(area*time)`
.. py:data:: distance
:attr:`~symplyphysics.symbols.classical_mechanics.orthogonal_distance` to the central plane of the slab.
Symbol:
:code:`z`
Latex:
:math:`z`
Dimension:
:code:`length`
.. py:data:: thickness
:attr:`~symplyphysics.symbols.classical_mechanics.thickness` of the slab.
Symbol:
:code:`h`
Latex:
:math:`h`
Dimension:
:code:`length`
.. py:data:: neutron_flux
:attr:`~symplyphysics.symbols.nuclear.neutron_flux` at a :attr:`~distance` from the central plane of the slab.
Symbol:
:code:`Phi`
Latex:
:math:`\Phi`
Dimension:
:code:`1/(area*time)`
.. py:data:: law
:code:`Phi = Phi_0 * cos(pi / h * z)`
Latex:
.. math::
\Phi = \Phi_{0} \cos{\left(\frac{\pi}{h} z \right)}