Efficiency of hydraulic press from force and height
===================================================

A real hydraulic press is never :math:`100%` efficient due to friction and other energy
losses. Its efficiency is the ratio of the useful work (given by the product of output
force and the height of the output side) to the expended work (given by the product of
input force and the height of the input side).

..
    TODO: find link

.. py:currentmodule:: symplyphysics.laws.hydro.efficiency_of_the_hydraulic_press_from_force_and_height

.. py:data:: output_force

    Output :attr:`~symplyphysics.symbols.classical_mechanics.force`.

Symbol:
    :code:`F_2`

Latex:
    :math:`F_{2}`

Dimension:
    :code:`force`


.. py:data:: output_distance

    :attr:`~symplyphysics.symbols.classical_mechanics.euclidean_distance` covered by the output piston.

Symbol:
    :code:`d_2`

Latex:
    :math:`d_{2}`

Dimension:
    :code:`length`


.. py:data:: input_force

    Input :attr:`~symplyphysics.symbols.classical_mechanics.force`.

Symbol:
    :code:`F_1`

Latex:
    :math:`F_{1}`

Dimension:
    :code:`force`


.. py:data:: input_distance

    :attr:`~symplyphysics.symbols.classical_mechanics.euclidean_distance` covered by the input piston.

Symbol:
    :code:`d_1`

Latex:
    :math:`d_{1}`

Dimension:
    :code:`length`


.. py:data:: efficiency

    :attr:`~symplyphysics.symbols.classical_mechanics.mechanical_efficiency` of the hydraulic press.

Symbol:
    :code:`eta`

Latex:
    :math:`\eta`

Dimension:
    :code:`dimensionless`


.. py:data:: law

    :code:`eta = F_2 * d_2 / (F_1 * d_1)`


    Latex:
        .. math::
            \eta = \frac{F_{2} d_{2}}{F_{1} d_{1}}